CBSE Class 11-science Answered
A stone is thrown vertically upwards with a velocity of 4.9 m/s. Calculate a) the maximum height reached. b) the time taken to reach the maximum height. c) the velocity with which it returns to the ground and d) the time taken to reach the ground.
Solutions: a) 1.225m b)0.5s c)4.9 m/s d)1s
Asked by kkdmmdsd | 12 Aug, 2019, 07:51: AM
Expert Answer
To get the maximum height h reached by stone, we need to use the formula, "v2 = u2 - 2gh " ,
where v is final velocity which is zero here, u is initial velocity and g is acceleration due to gravity.
hence h = u2 /(2g) = (4.9×4.9)/(2×9.8) = 1.225 m
To get the time taken to reach maximum height h, we need to use the formula , " v = u - g t ".
since final velocity v = 0, t = u/g = 4.9/9.8 = 0.5 s
Stone reaches the ground with same velocity as it was projected upwards,
i.e., its velocity when it reaches ground is 4.9 m/s
Downward flight time of stone is same as upward flight time ,
Hence time taken to reach ground from starting time = 0.5+0.5 = 1 s
Answered by Thiyagarajan K | 12 Aug, 2019, 09:03: AM
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