Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

a stone is projected vertically upwards with a velocity 10m/s find the maximum height reached by the body g=10m/s2
Asked by 5171508.8sujay | 21 Dec, 2020, 11:17: AM
answered-by-expert Expert Answer
Let us use the equation of motion " v2 = u2 + 2 aS " , where v is final velocity , u is initial velocity ,
a is acceleration and S is distance travelled
 
when stone is rached heighst distance h above ground, its final speed is zero. 
 
acceleration a = - g = -10 m/s2 , where g is acceleration due to gravity
 
initial spee u = 10 m/s 
 
hence h = u2 / (2g ) = ( 10 × 10 ) / ( 2 × 10) = 5 m 
Answered by Thiyagarajan K | 21 Dec, 2020, 11:46: AM
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by gundlasumathi93 | 31 Mar, 2024, 02:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by chhayasharma9494 | 31 Mar, 2024, 12:47: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by Machinenineha | 27 Mar, 2024, 05:28: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by nandichandi33 | 24 Mar, 2024, 09:21: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×