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Home / Doubts and Solutions/JEE/Physics

a stone is projected vertically upwards with a velocity 10m/s find the maximum height reached by the body g=10m/s2

Asked by 5171508.8sujay 21st December 2020, 11:17 AM
Answered by Expert
Answer:
Let us use the equation of motion " v2 = u2 + 2 aS " , where v is final velocity , u is initial velocity ,
a is acceleration and S is distance travelled
 
when stone is rached heighst distance h above ground, its final speed is zero. 
 
acceleration a = - g = -10 m/s2 , where g is acceleration due to gravity
 
initial spee u = 10 m/s 
 
hence h = u2 / (2g ) = ( 10 × 10 ) / ( 2 × 10) = 5 m 
Answered by Expert 21st December 2020, 11:46 AM
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