CBSE Class 10 Answered
A stone is dropped into a well and the sound of the splash is heard after 25/8 seconds later. If the velocity of sound in the air is 352.8 m/s,find the depth of the well.(g = 9.8 m/s^2)
Asked by acv27joy | 12 May, 2018, 07:35: PM
Expert Answer
Let S is depth of well and the dropped stone takes t1 seconds to reach the water surface. The we have
S = (1/2)×9.8×t12 = 4.9×t12 ....................(1)
let t2 be the time taken for the sound to reach observer. then we have
t2 = S/352.8 ..................(2)
substiute for S in (2) using (1)
t2 = (4.9×t12)/352.8 = t12/72 ........(3)
we are given t1+t2 = 25/8...........(4)
using (3) in (4), t1 + t12 / 72 = 25/8 ...(5)
by solving this quadratic equation (5) , we get t1 = 3 second.
Hence the depth S can be obtained from (1) : S = 4.9×3×3 = 44.1 m
Answered by Thiyagarajan K | 12 May, 2018, 10:03: PM
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