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A stone is dropped into a well and its splash is heard at the mouth of the well after an interval of 1.45s. Find the depth of the well. Given that velocity of sound in air at room temparature is 332m/s.
Asked by sujaysarkar84 | 05 Mar, 2015, 09:48: AM
answered-by-expert Expert Answer
begin mathsize 14px style Given colon Speed space of space sound space equals space 332 space straight m divided by straight s Time space taken space equals space 1.45 space straight s Distance space travelled space left parenthesis depth space of space the space well right parenthesis comma space straight d equals ? Speed space of space sound space wave space equals space fraction numerator 2 space cross times space distance space travelled over denominator time space taken end fraction space 332 space equals space fraction numerator 2 space cross times space straight d over denominator 1.45 end fraction 2 space straight d space equals space 332 space cross times space 1.45 straight d equals fraction numerator 332 space cross times space 1.45 over denominator 2 end fraction straight d equals fraction numerator 481.4 over denominator 2 end fraction equals 240.7 Thus comma space the space depth space of space the space well space is space 240.7 space straight m end style
Answered by Faiza Lambe | 05 Mar, 2015, 11:18: AM

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