CBSE Class 11-science Answered
A stone is dropped from a certain height which can reach the ground in 5s. It is stopped momentarily after 3s of its fall and then it is again released. The total time taken by the stone to reach the ground will be
A. 6s
B. 6.5s
C. 7s
D. 7.5s
Asked by shyamalimaborthakur89498 | 04 Aug, 2018, 08:50: PM
Expert Answer
First let us find the height above the ground from which the stone is dropped.
It is given that the stone reaches the ground in 5s.
Hence the height h = (1/2)×g×t2 = (1/2)×10×5×5 = 125 m
( g is assumed as 10 m/s2 )
Vertical distance travelled in initial 3 s, h1 = (1/2)×10×3×3 = 45 m
remaining distance h2 = 125-45 = 80 m
time taken t to travel remaining distance is given by, 80 = (1/2)×10×t2 , we get t = 4 s
Hence total time = 4+3 = 7 s
Answered by Thiyagarajan K | 04 Aug, 2018, 09:30: PM
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