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CBSE Class 9 Answered

A stone is allowed to fall down from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 ms-1. Calculate when and where the two stones will meet? (take g = 10ms-2)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

Let a stone A is allowed to fall from top of a height h = 100m

Its initial velocity u1 = 0

And a1 = +g = +10 ms-2

Another stone B is projected upwards from the ground with an initial velocity u2 = 25ms-1 and for it a2 = -g = -10 ms-2

Let the two stones meet at a point C at a distance y below A or (100-y) above B after a time t.

Then for stone A

For stone B

Answered by | 04 Jun, 2014, 03:23: PM

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