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A standard tuning fork A has a frequency 480Hz. Another tuning fork B gives 6 beats with it. B is slightly filed and now the beat frequency is found to be 2.Find the original frequency of B.

Asked by 24th February 2013, 12:36 PM
Answered by Expert
Answer:
nB-480=6
nB>nA as B is slightly filed and now the beat frequency is found to be less.
so nB=486Hz
Answered by Expert 26th February 2013, 5:56 PM
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