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a sq.x sq.-3abx+ 2b sq. = 0

Asked by pulkithere1 17th February 2011, 9:47 AM
Answered by Expert
Answer:
Dear student,
a2x2 -3abx + 2b2 = 0
a2x2 -abx - 2abx + 2b2 = 0
ax(ax - b) - 2b(ax - b) = 0
(ax - b)(ax - 2b) = 0
x = b/a or x = 2b/a
We hope that clarifies your query.
Regards,
Team
TopperLearning
Answered by Expert 20th February 2011, 1:04 PM
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