CBSE Class 9 Answered
A sprinter of 100 m race, covers 4 m in first second, 30 m in next 4 seconds and 52m in amother 4 seconds and finishes the race in 10 seconds. (i)Calculate the average speed of the sprinter ? (ii) what is the peak value attained by the sprinter ? (iii) during which time interval is the acceleration is the highest ? (iv) Plot the distance time graph and velocity time graph for the race ? (iv) show on the graph the velocity of the sprinter at the end of 5 seconds ?
Asked by Vikas | 06 Jul, 2017, 12:32: PM
Expert Answer
(ii) For all the time intervals we need to calculate the initial velocity, acceleration, displacement and the final velocity
Formulas used:
s = ut + (1/2)at2 and v = u + at
Time s | 0 | 1 | 5 | 9 | 10 |
Distance m | 0 | 4 | 34 | 86 | 100 |
Velocity m/s | 0 | 8 | 7 | 19 | 9 |
So, peak velocity attained by the is 19 m/s at the end of the 9th second.
(iii) Acceleration is highest between 5th to 9th second. It is 3 m/s2.
(iv)
(v)
Mark the points from 5 second on the graph and note down the corresponding reading on the velocity scale.
Then, calculate the slope.
Answered by Yashvanti Jain | 06 Jul, 2017, 06:48: PM
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