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A solution of a salt of a metal of atomic weight 112 was electrolysed for 150 minutes with a current of 0.15 amperes. The weight of metal deposited was 0.783 mg; find the equivalent weight and valency of the metal in the salt.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

Given, I = 0.15 ampere, t = 150 ×60 seconds

 
Q = I × t
 
Q = 0.15 ×150 × 60 coulombs = 1350 coulombs
 
Hence 1350 coulombs of electricity deposit = 0.783 gm of metal
96540 coulombs of electricity =
Answered by Expert 4th June 2014, 3:23 PM
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