###### Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

# A solution of a salt of a metal of atomic weight 112 was electrolysed for 150 minutes with a current of 0.15 amperes. The weight of metal deposited was 0.783 mg; find the equivalent weight and valency of the metal in the salt.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

Given, I = 0.15 ampere, t = 150 ×60 seconds

Q = I × t

Q = 0.15 ×150 × 60 coulombs = 1350 coulombs

Hence 1350 coulombs of electricity deposit = 0.783 gm of metal
96540 coulombs of electricity =
Answered by Expert 4th June 2014, 3:23 PM
Rate this answer
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

Your answer has been posted successfully!
RELATED STUDY RESOURCES :
CBSE Class-12-science QUESTION ANSWERS

### Latest Questions

CBSE XII Science Chemistry
Asked by govtsecschoolnayaganv051 16th June 2019, 10:55 PM
CBSE XI Science Physics
Asked by pb_ckt 16th June 2019, 9:36 PM
CBSE X History
Asked by PRAMOD122497 16th June 2019, 9:06 PM