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A solution containing 0.20g of Ca salt is passed through a column containing the hygrogen form of a strong acid cation exchange resin.The resulting solutions is neutralised with 35.0ml of 0.10 M sodium hydroxide.What is the no of moles of Ca 2+ per g of the Ca salt?

 

Asked by minipkda 18th June 2018, 5:59 PM
Answered by Expert
Answer:
Given:
 
Weight of salt = 0.20 g
 
Molarity of NaOH = 0.10 M
 
Volume of NaOH = 35.0ml 
 
Reaction space equation colon

Ca to the power of 2 plus end exponent space plus space HCl subscript open parentheses resin close parentheses end subscript space rightwards arrow space 2 straight H to the power of plus space plus space Ca to the power of 2 plus end exponent

Titration space with space NaOH

straight H to the power of plus space plus space NaOH space rightwards arrow space straight H subscript 2 straight O space plus space Na to the power of 2 plus end exponent

No. space of space moles space of space straight H to the power of plus space equals space Molarity space cross times space Volume space in space litre

space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.1 cross times bevelled 35 over 1000

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3.5 space cross times 10 to the power of negative 3 end exponent space mole


No space of space moles space of space Ca to the power of 2 plus space end exponent space equals 1 half No. space of space moles space of space straight H to the power of plus
space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 3.5 space cross times 10 to the power of negative 3 end exponent over denominator 2 end fraction

For space 0.2 space straight g space of space salt space equals space fraction numerator 1.75 cross times 10 to the power of negative 3 end exponent over denominator 0.2 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 8.75 space cross times 10 to the power of negative 3 end exponent space mole
 
No. of moles of Ca2+ is 8.75×10-3 mole.
Answered by Expert 2nd July 2018, 2:42 PM
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