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A solid weighs 30 gf in air and 26 gf when completely immersed in a liquid of relative density 0.8.  Find : (i) the volume of the solid and (ii) the relative density of the solid.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

Given, weight of solid in air = 30 gf and weight of solid in liquid = 26 gf., R.D of liquid = 0.8

Therefore, Density of liquid = 0.8 g cm-3

(i) Let V be the volume of the solid.

Weight of liquid displaced = Volume of liquid displaced xdensity of liquid x g

                                          = V 0.8g dyne

                                         = V 0.8 gf

Loss in the weight of the solid when immersed in the liquid = 30 - 26 = 4gf

But the weight of liquid displaced is equal to the loss in weight of the solid when immersed in liquid.

Therefore, Vx0.8 = 4 or V =  = 5 .

(ii) Given, weight of solid = 30gf

Therefore, Mass of solid = 30 g

Density of solid =

Hence relative density of solid = 6

Answered by Expert 4th June 2014, 3:23 PM
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