. A solid cylinder of mass m 4kg and radius
R-10cm has two ropes wrapped around it, one
near each end. The cylinder is held horizontally
by fixing the two free ends of the cords to the
hooks on the ceiling such that both the cords
are exactly vertical. The cylinder is released
to fall under gravity. Find the tension along
the strings.
1) 6.53N 2) 5.23N 3) 3.23N 4) 4.43N
. A solid cylinder of mass m 4kg and radius
R-10cm has two ropes wrapped around it, one
near each end. The cylinder is held horizontally
by fixing the two free ends of the cords to the
hooks on the ceiling such that both the cords
are exactly vertical. The cylinder is released
to fall under gravity. Find the tension along
the strings.
1) 6.53N 2) 5.23N 3) 3.23N 4) 4.43N
Asked by chandanbr6004
25th November 2017,
2:20 PM
Answered by Expert
Answer:
Let a be the acceleration when the cylinder is falling freely.
m × a = m × g - 2×T ............................(1)
Let r be the radius of cylinder. If torque acting on both the ends are similar then net torque is given by
...........................(2)Where I is moment of inertai and α is angular acceleration due to rod rotation.
if we substitute for I and α in the above equation we get
Substituting the above equation for T in eqn.(1) , we get a = (2/3)g
Hence T = (1/4)×4×(2/3)x9.8 = 6.53 N
Answered by Expert
29th November 2017,
3:46 PM
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