Contact

For Enquiry

10:00 AM to 7:00 PM IST all days.

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

022-62211530

Mon to Sat - 10 AM to 7 PM

# . A solid cylinder of mass m 4kg and radius R-10cm has two ropes wrapped around it, one near each end. The cylinder is held horizontally by fixing the two free ends of the cords to the hooks on the ceiling such that both the cords are exactly vertical. The cylinder is released to fall under gravity. Find the tension along the strings. 1) 6.53N 2) 5.23N 3) 3.23N 4) 4.43N

Asked by chandanbr6004 25th November 2017, 2:20 PM
Let a be the acceleration when the cylinder is falling freely.

m × a =  m × g - 2×T  ............................(1)

Let r be the radius of cylinder. If torque acting on both the ends are similar then net torque is given by

...........................(2)
Where I is moment of inertai and α is angular acceleration due to rod rotation.

if we substitute for I and α in the above equation we get

Substituting the above equation for T in eqn.(1) , we get  a = (2/3)g

Hence T = (1/4)×4×(2/3)x9.8 = 6.53 N
Answered by Expert 29th November 2017, 3:46 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10