ICSE Class 9 Answered
A solid body weighs 2.10 N in air. Its relative density is 8.4. How much will the body weigh if placed
(i) in water
(ii) in a liquid of relative density 1.2?
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Given : Weight of the body in air W = 2.10 N, R.D of body = 8.4, weight of the body in water W1 = ?
R.D = 
Therefore 8.4 = 
or 8.4 (2.1 - 
) = 2.1 or 
Thus weight of body in water = 1.85 N
(ii) Upthrust due to water = 
Upthrust due to liquid = Upthrust due to water 
R.D of liquid
=0.25 1.2 = 0.30 N
Therefore, Weight of the body in liquid = Weight of the body in air - Upthrust due to liquid
= 2.10 - 0.30 = 1.8 N
Answered by | 04 Jun, 2014, 03:23: PM
ICSE 9 - Physics
Asked by baneetkumar67 | 29 Aug, 2018, 05:07: PM
ANSWERED BY EXPERT
