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A solid body weighs 2.10 N in air.  Its relative density is 8.4.  How much will the body weigh if placed

(i) in water

(ii) in a liquid of relative density 1.2?

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

Given : Weight of the body in air W = 2.10 N, R.D of body = 8.4, weight of the body in water W1 = ?

R.D =

Therefore 8.4 =

or 8.4 (2.1 - ) = 2.1 or

Thus weight of body in water = 1.85 N

(ii) Upthrust due to water =

Upthrust due to liquid = Upthrust due to water R.D of liquid

                                    =0.25 1.2 = 0.30 N

Therefore, Weight of the body in liquid = Weight of the body in air - Upthrust due to liquid

                                                              = 2.10 - 0.30 = 1.8 N 

Answered by Expert 4th June 2014, 3:23 PM
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