Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

CBSE - XI Science - Physics - Waves

A rope of length L and mass m hangs freely from the ceiling.The velocity of transverse  as a function of position x along the rope is proportional to
(a)x to the power of 0
(b)square root of x
(c)bevelled fraction numerator 1 over denominator square root of x end fraction

Asked by Akanksha Mishra 20th March 2015, 3:35 PM
Answered by Expert


The velocity of transverse wave on a rope is given as
begin mathsize 14px style straight v equals square root of straight T over straight mu end root end style
Now, when the rope is hanging, the tension in the string depends on the position x along the rope.
T = μgx
Hence, we have
begin mathsize 14px style straight v equals square root of μgx over straight mu end root equals square root of gx end style
Hence, the correct option is (b)
Answered by Expert 20th March 2015, 6:28 PM

Rate this answer

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Your answer has been posted successfully!