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Home / Doubts and Solutions/NEET/Physics

a rock is thrown straight up with twice the initial the velocity of another. how much higher will the first  rock be at its apex?

 

Asked by meghanaprabhu1612 22nd October 2020, 7:56 PM
Answered by Expert
Answer:
Let rock-1 is thrown upwards with speed 2u and rock-2 is thrown upward with speed u.
 
Height h1 reached by the first rock = ( 2u )2 / (2g) = ( 4 u2 ) / ( 2g )
 
Height h2 reached by the second rock =  u2 / (2g) = u2 / (2g )
 
First rock will reach 4 times of height reached by second rock
Answered by Expert 22nd October 2020, 8:39 PM
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