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CBSE Class 9 Answered

A rectangular block of iron metal of dimensions begin mathsize 12px style 22 space cm space cross times space 14 space cm space cross times space 7 cm end style is recasted into a cylindrical vessel of height 14 cm. Calculate its radius.
Asked by Topperlearning User | 27 Oct, 2017, 01:35: PM
answered-by-expert Expert Answer

Dimensions of the rectangular block are,

Length (l) = 22 m, breadth (b) = 14 m and height (h) = 7 m

Volume of tank (V) = lbh = 2156 m3

This rectangular block is recasted into a cylindrical vessel.

Height of the cylindrical vessel (h) = 14 cm

Let r be the radius of the cylindrical vessel and V1 denote the volume of the vessel.

Thus, volume of cylindrical wire = volume of cubical mass

begin mathsize 12px style straight V subscript 1 space equals space straight V
22 over 7 cross times straight r cross times straight r cross times 14 space equals space 2156
straight r squared space equals space fraction numerator 2156 cross times 7 over denominator 22 cross times 14 end fraction
straight r squared space equals space 49
straight r space equals space 7 space cm end style

Thus, radius of the cylindrical vessel is 7 cm.

Answered by | 27 Oct, 2017, 03:35: PM
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