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A ray of light incident on an equilateral glass prism shows minimum deviation of 30 degrees speed of light through prism is  
Asked by raog11 | 19 Jul, 2018, 10:32: PM
answered-by-expert Expert Answer
The relation for refractive index μ of prism that is related to angle of prism A, minimum deviation Dm is given by,

begin mathsize 12px style mu space equals space fraction numerator sin open square brackets open parentheses A plus D subscript m close parentheses divided by 2 close square brackets over denominator sin open parentheses A divided by 2 close parentheses end fraction space equals space fraction numerator sin open square brackets open parentheses 60 plus 30 close parentheses divided by 2 close square brackets over denominator sin space 30 end fraction space equals space square root of 2 space end root end style

Refractive index of medium  = begin mathsize 12px style fraction numerator S p e e d space o f space l i g h t space i n space v a c u u m over denominator S p e e d space o f space l i g h t space i n space m e d i u m end fraction end style

hence, speed of light through prism = (3×108 ) / √2  = 2.121×108  m/s
Answered by Thiyagarajan K | 20 Jul, 2018, 11:21: AM

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