CBSE Class 10 Answered
A ray of light falls on the surface of a spherical paper weight making an angle A with the normal and is refracted in the medium at an angle B. Find the angle of deviation of the emergent ray from the direction of the incident ray in terms of A and B.
Asked by acv27joy | 16 Dec, 2018, 06:13: PM
Expert Answer
Figure shows an incident ray PQ which makes an angle A with normal is refracted and the angle of refraction is B.
When the refracted ray incident at R, it will make an agle B with normal, because both normals at Q and R will meet
to form an isoceless triangle(OQ and OR are radius). Since angle of incidence at R is same as angle of refraction,
angle of emergence is A as per law of refraction.
By extending the incident ray and emergent ray at the point of incidence and at the point of emergence,
we can calculate the angle of deviation between incident ray and emergent ray.
TQR = TRQ = (A-B)
Hence angle of deviation between incident and emergent ray = UTR = 2(A-B) [ sum of interior angles of ΔQTR ]
Answered by Thiyagarajan K | 16 Dec, 2018, 11:04: PM
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