ICSE Class 10 Answered
A pulley system pulls a load of 600N by an effort of 200N.If the resistance due to the movable parts of a machine is 400N,find:
1.MA
2.VR
3.No.of pulley
4.Efficiency
Asked by pb_ckt | 04 Feb, 2019, 12:27: PM
Expert Answer
Load (L) = 600 N
Resistance due to movable parts = 400 N
Effort (E) = 200 N
1.
3. The mechanical advantage of the pulley system = number of pulleys (n) = 5
2. Velocity ratio (VR) = number of pulleys = 5
4. thus, actual mechanical advantage (MA)= n - (w/E) = 5 - (400/200) = 3
Thus, Efficiency
Answered by Shiwani Sawant | 04 Feb, 2019, 04:41: PM
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