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Home / Doubts and Solutions/JEE/Physics

A pt moves in a straight line under the retardation -kv where k is a constant.If the initial velocity is u,the distance covered in t sec is

Asked by m.nilu 20th July 2018, 9:52 PM
Answered by Expert
Answer:
Distance S = u×t - (1/2)×(kv)×t2
Answered by Expert 21st July 2018, 11:25 AM
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