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a proto an an alpha particle enter a uniform magnetic field perpendicular with same speed.if proton take 20micro second to make 50revolutin,then  the periodic time for the alpha particlewould be

  

Asked by santhakumari1908 15th September 2018, 8:44 AM
Answered by Expert
Answer:
when a charge q enters in magnetic field B with speed v, it moves in a circular path of radius R which is related to charge q,
mass of charged particle m and flux density of magnetic field B as given by,
 
q×B×v = m×v2/R ................(1)
 
if we substitute angular velocity ω = v×R in eqn. (1) and after simplification we get ω=B×q/m ...............(2)
 
begin mathsize 12px style omega subscript p over omega subscript alpha space equals space q subscript p over q subscript alpha cross times m subscript alpha over m subscript p space equals space 2 space space space space o r space space space space space space omega subscript alpha space equals space 1 half omega subscript p space space space end subscript space space o r space space fraction numerator 2 pi over denominator T subscript alpha end fraction space equals space space 1 half cross times fraction numerator 2 pi over denominator T subscript p end fraction space space space o r space space space T subscript alpha space equals space 2 space T subscript p

H e n c e space T subscript alpha space equals space 2 cross times fraction numerator 20 space mu s over denominator 50 end fraction space equals space 0.8 space mu s end style

Answered by Expert 15th September 2018, 11:13 AM
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