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A projectile is thrown with a speed u,at an angle theta to an inclined plane of inclination beta.The angle theta at which the projectile is thrown such that it strikes the inclined plane normally is..

Asked by m.nilu 4th July 2018, 3:14 PM
Answered by Expert
Answer:
 
The figure to answer for this question is drawn as per my understanding.
We have to assume the projectile is hitting the inclined plane at a distance L on the inclined plane, from the projection point .
 
The velocity vector along with the resolved horizontal componenet and vertical component are shown in the figure.
User may workout how the velocity vector makes angle (90-β) with the horizontal component.
 
From resolved vector components, we have,        begin mathsize 12px style fraction numerator v over denominator u space cos theta end fraction space equals space tan left parenthesis 90 minus beta right parenthesis space equals space c o t space beta space o r space space space space v squared space equals space u squared cos squared theta space c o t squared beta space..................... left parenthesis 1 right parenthesis
end style
where v is the vertical component of velecity vector at point A, u is the projection velocity. Refer the figure for angles.
 
From projectile motion, we have, begin mathsize 12px style v squared space equals space u squared space sin squared theta space minus space 2 space g space open parentheses L space sin beta close parentheses space...................... left parenthesis 2 right parenthesis end style
from (1) and (2), we can write,   begin mathsize 12px style u squared space cos squared theta space c o t squared beta space equals space u squared space sin squared theta space minus space 2 space g left parenthesis L space sin space beta right parenthesis end style ........................(3)
Eqn.(3) is the relation between u, L, β and θ . Using trignometry and algebrical simplification ,
we can get a relation for  θ in terms of other variables as given below ( I leave this as exercise to user)
 
begin mathsize 12px style theta space equals space sin to the power of negative 1 end exponent open parentheses square root of cos squared beta space plus space fraction numerator 2 space g space L over denominator u squared end fraction space sin squared beta end root close parentheses end style

Answered by Expert 6th July 2018, 11:36 AM
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