A projectile is fired vertically upward from the surface of earth with a velocity of kvE, where vE is the escape velocity and k<1. Neglecting air resistance, the maximum height to which it will rise, measured from the centre of earth is (R = radius of earth)
(a) R/1-k^2
(b) R/k^2
(c) 1-k^2/R
(d) k^2/R
Asked by nasir.mirza
13th June 2018,
7:11 PM
Answered by Expert
Answer:
When the projectile leaves the earth's surface, its kinetic energy Ki 
where vE is escape velocity
at earth's surface , its poetial energy Ui 
where M and R are mass and radius of earth respectively. m is mass of projectile.
When the projectile reaches the maximum height h, its kinetic energy Kf is zero.
Its potential energy Uf at maximum height h is given by, 
By conservation of energy, we have
.................(1)By substituting 
in eqn(1) and further simplification we get 
in eqn(1) and further simplification we get
Answered by Expert
14th June 2018,
4:15 PM
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