CBSE Class 11-science Answered
A projectile as a range of100m and as a maximum height of 20m. At what angle it was fired?
Asked by ommnayak2003 | 03 Jun, 2019, 07:52: PM
Expert Answer
Let u be the projection speed and α be the projection angle.
Range of projectile = .............................(1)
Maximum height = ...................................(2)
by dividing eqn.(1) by eqn.(2), we get, sin 2α / sin2α = 5 or 2 sinα cosα = 5 sin2α
hence tan α = 2/5 or α = tan-1(0.4) = 21.8 °
Answered by Thiyagarajan K | 03 Jun, 2019, 09:18: PM
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