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CBSE Class 11-science Answered

A projectile as a range of100m and as a maximum height of 20m. At what angle it was fired?
Asked by ommnayak2003 | 03 Jun, 2019, 07:52: PM
answered-by-expert Expert Answer
Let u be the projection speed and α be the projection angle.
 
Range of projectile = begin mathsize 12px style fraction numerator u squared sin 2 alpha over denominator 2 space g end fraction space equals space 100 space m end style .............................(1)
Maximum height = begin mathsize 12px style fraction numerator u squared sin squared alpha over denominator 2 space g end fraction space equals space 20 space m end style  ...................................(2)
by dividing eqn.(1) by eqn.(2), we get,    sin 2α / sin2α = 5   or     2 sinα cosα = 5 sin2α    
 
hence  tan α = 2/5   or   α = tan-1(0.4) = 21.8 °
Answered by Thiyagarajan K | 03 Jun, 2019, 09:18: PM
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