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  A potentiometer wire of 1000 cm length is adjusted to give a null point at 500 cm with a standard cell of emf 1.018 V. The emf of a cell which gives null point at 600 cm is
Asked by chetansathe64 | 28 Jun, 2020, 06:51: PM
answered-by-expert Expert Answer
T h e space r e l a t i o n space b e t w e e n space t h e space E M F thin space i s space g i v e n space b
E subscript 1 over E subscript 2 equals l subscript 1 over l subscript 2
w h e r e E subscript 1 space a n d space space E subscript 2 space a r e space t h e space e m f space o f space t h e space c e l l space a n d space l subscript 1 space a n d space l subscript 2 space a r e space t h e space l e n g t h space o f space b a l a n c e space p o i n t
fraction numerator 1.018 over denominator E subscript 2 end fraction equals 500 over 600
E subscript 2 equals 600 over 500 cross times 1.018
E subscript 2 equals 1.2216
Answered by Utkarsh Lokhande | 29 Jun, 2020, 11:32: AM
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