 ###### Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

# A positive number is divided into two parts such that the sum of the squares of the two parts is 208.The square of the larger part is 8 times the smaller part. Taking 'x' as the smaller part, find the number.

Asked by Janani S 21st July 2012, 11:04 PM
Answered by Expert
Answer:

Let the two numbers be x and y, y being the bigger number. From the given information,

x2 + y2 = 208  ..... (i)

y2 = 18x         ..... (ii)

From (i), we get y2=208 - x2. Putting this in (ii), we get,

208 - x2 = 18x

x2 + 18x - 208 = 0

x2 + 26X - 8X - 208 = 0

x(x + 26) - 8(x + 26) = 0

(x - 8)(x + 26) = 0

x can't be a negative number , hence x = 8

Putting x = 8 in (ii), we get y2 = 18 x 8=144

- y = 12

Hence, the two numbers are 8 and 12.
Answered by Expert 22nd July 2012, 9:44 PM
Rate this answer
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

Your answer has been posted successfully!
RELATED STUDY RESOURCES :
ICSE Class-10 QUESTION ANSWERS

### Latest Questions

NEET NEET Chemistry Asked by Mrinal 20th May 2019, 10:07 PM