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CBSE Class 12-science Answered

a point charge Q1  = 100 microcoulomb is placed at a point A (1,0,1) and another point charge Q2 is placed at point B (4,4,2) find : a] magnitude of electrostatic interaction force acting between them b] find force on A due to B in vector form c] find force on B due to A in vector form.  
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Asked by resmitdholariya | 21 Jun, 2020, 06:32: PM
answered-by-expert Expert Answer
F equals fraction numerator K Q subscript 1 Q subscript 2 over denominator r squared end fraction r with hat on top a right parenthesis M a g n i t u d e space o f space f o r c e space b e t w e e n space t h e space t w o space c h a r g e s space i s space g i v e n space b y F equals fraction numerator K Q subscript 1 Q subscript 2 over denominator r squared end fraction r equals square root of open parentheses 4 minus 1 close parentheses squared plus open parentheses 4 minus 0 close parentheses squared plus open parentheses 2 minus 1 close parentheses squared end root equals square root of 26 b right parenthesis F o r c e space o n space A space d u e space t o space v e c t o r space B stack B A with rightwards arrow on top equals open parentheses 4 minus 1 close parentheses i plus open parentheses 4 minus 0 close parentheses j plus open parentheses 2 minus 1 close parentheses k equals 3 i plus 4 j plus k open vertical bar stack B A with rightwards arrow on top close vertical bar equals square root of open parentheses 4 minus 1 close parentheses squared plus open parentheses 4 minus 0 close parentheses squared plus open parentheses 2 minus 1 close parentheses squared end root stack B A with logical and on top equals fraction numerator stack B A with rightwards arrow on top over denominator open vertical bar stack B A with rightwards arrow on top close vertical bar end fraction r with logical and on top equals stack B A with logical and on top equals fraction numerator 3 i plus 4 j plus k over denominator square root of open parentheses 4 minus 1 close parentheses squared plus open parentheses 4 minus 0 close parentheses squared plus open parentheses 2 minus 1 close parentheses squared end root end fraction F with rightwards arrow on top subscript A B end subscript equals fraction numerator K Q subscript 1 Q subscript 2 over denominator r squared end fraction r with hat on top F with rightwards arrow on top subscript A B end subscript equals fraction numerator K Q subscript 1 Q subscript 2 over denominator open parentheses square root of 26 close parentheses squared end fraction fraction numerator 3 i plus 4 j plus k over denominator square root of open parentheses 4 minus 1 close parentheses squared plus open parentheses 4 minus 0 close parentheses squared plus open parentheses 2 minus 1 close parentheses squared end root end fraction c right parenthesis F o r c e space o n space B space d u e space t o space A F with rightwards arrow on top subscript B A end subscript equals fraction numerator K Q subscript 1 Q subscript 2 over denominator open parentheses square root of 26 close parentheses squared end fraction fraction numerator negative 3 i minus 4 j minus k over denominator square root of open parentheses 4 minus 1 close parentheses squared plus open parentheses 4 minus 0 close parentheses squared plus open parentheses 2 minus 1 close parentheses squared end root end fraction
Answered by Utkarsh Lokhande | 23 Jun, 2020, 11:05: AM

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