Please wait...
Contact Us
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry



Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9372462318 / 9987178554

Mon to Sat - 10 AM to 7 PM

A particle starts from rest and traverses a distance l with uniform acceleration, then moves uniformly over a further distance 2l and finally comes to rest after moving a further distance 3l under uniform retardation. Assuming entire motion to be rectilinear motion, the ration of average speed over the journey to the maximum speed on its way is:

Asked by Arushi Juyal 12th November 2017, 3:22 PM
Answered by Expert
The entire travel is divided into three parts (1) accelerated travel (2) Uniform speed travel (3) travel with retarding speed
for each part let us assume the time duration is t1 , t2 and t3.
For the part-1, let us assume the acceleration is a.
The duration t1 and the final velocity at the end of part-1 travel distance l  is given by
From the above equations we can get
For the second travel part, which is travelled with uniform speed   a×t1 , we get the relation for
distance travelled as given below and we can get the relation for travel duration t2 
for third part, initial velocity is at1  and this motion is retarded and let us assume retardation is r. 
By considering the travel distance 3l and final velocity is zero we get the following two equations 
By substituting for t1 in the above second equation we get   r = a/3.
Substituting for r and t1 in the first equation, we get 
So the required ratio of average speed to maximum speed is given by 
By Substituting for t1, t2 and t3, we will get the ratio as 3/5 after simplification

Answered by Expert 13th November 2017, 12:01 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 10/10

Your answer has been posted successfully!

Free related questions

5th July 2020, 12:04 AM

Chat with us on WhatsApp