CBSE Class 11-science Answered
A particle of mass m is at rest at the origin at time t= 0. Is subjected to a force F(t)= Foe-bt in the x direction. Graphically show the variation of speed with time and justify your answer.
Asked by sarasija123 | 04 Jun, 2018, 08:13: PM
Expert Answer
I assume the force F(t) = F0exp(-b×t)
It is assumed that F0 and b are constants
Acceleration a = dv/dt = F(t)/m = (F0/m)×exp(-b×t)
dv = (F0/m)×exp(-b×t)dt
By integrating above, we get speed, v(t) = (-1/b)(F0/m)×exp(-b×t)
The graph shown below is drawn for the above speed function v(t) by assuming (F0/m)=10 and b=0.5
Answered by Thiyagarajan K | 05 Jun, 2018, 10:26: AM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT
