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A particle of mass 'm' moving towards the east with speed 'v' collides with another particle of same mass and same speed 'v' moving towards the north. If the two particles stick to each other, the new particle of mass 2m will have a speed of?

Asked by nasir.mirza 13th June 2018, 10:47 PM
Answered by Expert
Answer:
In cartesian coordinate system, First particle moving towards East with speed v. hence its momentum begin mathsize 12px style v cross times i with rightwards arrow on top end style
Second particle moving towards North with speed v, hence its momentum begin mathsize 12px style v cross times j with rightwards arrow on top end style
where begin mathsize 12px style i with rightwards arrow on top space a n d space j with rightwards arrow on top end style are unit vectors in +x direction and +y direction respectively
Initial momentum before collision = begin mathsize 12px style m v cross times i with rightwards arrow on top plus space m v cross times j with rightwards arrow on top space equals space m v cross times open parentheses i with rightwards arrow on top plus space j with rightwards arrow on top close parentheses................... left parenthesis 1 right parenthesis end style
Let begin mathsize 12px style w with rightwards arrow on top end style be the velocity of combined mass 2m. Momentum after collision = begin mathsize 12px style 2 m cross times w with rightwards arrow on top end style...............(2)
by equating (1) and (2) and using conservation of momentum, we get begin mathsize 12px style w with rightwards arrow on top equals space v over 2 open parentheses i with rightwards arrow on top plus j with rightwards arrow on top close parentheses end style
magnatiude of begin mathsize 12px style w with rightwards arrow on top end style is v/√2
hence the combined mass 2m will move with speed v/√2 in NE direction
Answered by Expert 14th June 2018, 10:10 AM
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