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A particle is projected vertically upwards.wt will be the ratio of time at 3/4 of its gr8st height?

Asked by 12th June 2008, 7:57 PM
Answered by Expert
Answer:

At greatest height,

t=u/g,h=u2/2g

 

and 3/4 of greatest height,

3/4h=ut' - (1/2)gt'2

on solving, t'=t(/2

or t'/t=0.5

Answered by Expert 22nd July 2008, 10:25 PM
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