CBSE Class 9 Answered
A particle is projected upward with speed 105 m/s done the time after which it is hit the ground is:
1.20 s
2.21 s
3.22 s
4.25 s
Asked by santoshkumargupta644 | 25 Jan, 2021, 09:01: AM
Expert Answer
Time t to reach highest point , t = ( u / g )
where u is initial projection speed and g is acceleration due to gravity.
t = 105 / 9.8 = 10.71 s
Time taken from highest point to ground also 10.71 s
Hence, Time to reach ground = 2 × 10.71 = 20.42 s ≈ 20s
Answered by Thiyagarajan K | 25 Jan, 2021, 12:19: PM
Application Videos
Concept Videos
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 08 Feb, 2024, 06:45: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 08 Feb, 2024, 12:32: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 08 Feb, 2024, 12:13: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 09:50: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 09:00: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 08:44: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 08:24: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by sadhanaasadhanaa67 | 04 Feb, 2024, 12:27: PM
ANSWERED BY EXPERT