###### Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

# a particle is projected from ground with an initial velocity of 20 m per sec at an angle of 30 degree with the horizontal. wht is magnitude of change in 0.5 sec?

Asked by dharya21 3rd July 2010, 12:00 AM
Answered by Expert
Answer:
Given, u = 20 m/s
θ = 300
Assuming that your question was about change in magnitutde of Velocity, we can say

ux = u cosθ = 20xcos30 = 20x = 10m/s
uy = u sinθ = 20xsin30 = 20x1/2 = 10 m/s

ax = 0 m/s2
ay = -g = -10 m/s2

Now change in velocity after 0.5 seconds is,

vx = ux + axt = 10 + 0 = 10 m/s
vy = uy + ayt = 10 + (-10x0.5) = 10-5 = 5 m/s

So, the magnitude of final velocity after 0.5 seconds is, v =
therefore, v =
=
=
= 18.03 m/s

Team,
Topper Learning
Answered by Expert 19th July 2010, 11:32 AM
Rate this answer
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer 9/10

Your answer has been posted successfully!
RELATED STUDY RESOURCES :
CBSE Class-11-science QUESTION ANSWERS