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A particle is moving along a straight line according to x = t ^ 2-4t + 10. (1) The initial velocity of the particle will be (2) At t = 2sec. The velocity of the particle will be. (3) Time interval 0 to 2sec. Calculate the average velocity of the particle in?

Asked by surabhilakhara7299 25th May 2021, 8:04 AM
Position x(t) = ( t2 - 4 t + 10 ) m

velocity , v(t) = ( dx/dt ) = 2t - 4

(1) Initial velocity at t = 0 ,  v(0)  = ( 0 - 4 ) m/s = - 4 m/s

(2) velocity at t = 2 s , v(2) = 2 ( 2 ) - 4 = 0 m/s

(3)

Position at t = 0 , x(0) = 0 - 0 + 10 = 10 m

Position at t = 2 , x(2) = 4 -8 +10 = 6 m

displacement = ( 6 - 10 ) m = - 4 m

average velocity = displacement / time = -4 m / 2 s  = -2 m/s

Answered by Expert 25th May 2021, 10:55 AM
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