NEET Class neet Answered
A particle is moving along a straight line according to x = t ^ 2-4t + 10.
(1) The initial velocity of the particle will be
(2) At t = 2sec. The velocity of the particle will be. (3) Time interval 0 to 2sec. Calculate the average velocity of the particle in?
Asked by surabhilakhara7299 | 25 May, 2021, 08:04: AM
Expert Answer
Position x(t) = ( t2 - 4 t + 10 ) m
velocity , v(t) = ( dx/dt ) = 2t - 4
(1) Initial velocity at t = 0 , v(0) = ( 0 - 4 ) m/s = - 4 m/s
(2) velocity at t = 2 s , v(2) = 2 ( 2 ) - 4 = 0 m/s
(3)
Position at t = 0 , x(0) = 0 - 0 + 10 = 10 m
Position at t = 2 , x(2) = 4 -8 +10 = 6 m
displacement = ( 6 - 10 ) m = - 4 m
average velocity = displacement / time = -4 m / 2 s = -2 m/s
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