CBSE Class 11-science Answered
A object moving with speed of 6.25 m/s, is decelerated at a rate given by a=-2.5√v, where v is the instantaneous speed. The time taken by the object to come to rest would be
Asked by binayakbiswas | 16 Jul, 2019, 09:50: PM
Expert Answer
Acceleration a = dv/dt = -2.5√v
Where T is time taken by the object to come to rest
Answered by Thiyagarajan K | 16 Jul, 2019, 10:49: PM
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