ICSE Class 6 Answered
A nut can be opened by a lever of length 0.25m by applying a force of 80N. What should be the length of lever, if a force of 32 N is enough to open the nut?
Asked by ploganathan9 | 14 Jan, 2020, 07:45: PM
Expert Answer
The turning effect is same in both cases and thus given by,
T1 = T2
Thus,
(Load)1 × Lever arm = (Load)2 × Lever length
80 N × 0.25 = 32 × Lever length
Lever length = (80 N × 0.25) / 32
Lever length = 0.625 m
Answered by Shiwani Sawant | 15 Jan, 2020, 10:03: AM
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