Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (North)

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

8788563422

Mon to Sat - 10 AM to 7 PM

A number consists of two digits whose sum is 9. The number formed by reversing the digits exceeds twice the original number by 18. Find the original Number.

Asked by Abhirami Prabakar 15th December 2013, 7:00 PM
Answered by Expert
Answer:
Let the number be xy = 10x + y
Given: x + y = 9      ... (1)
Reverse number = 2 x Original number + 18
10y + x = 2(10x + y) + 18
10y + x = 20x + 2y + 18
19x - 8y + 18 = 0       ... (2)
 
Substituting the value of y from (1) in (2), we get,
19x - 8(9 - x) + 18 = 0
19x - 72 + 8x + 18 = 0
27x = 54
x = 2
So, y = 9 - 2 = 7
 
Thus, the original number is 27.
Answered by Expert 15th December 2013, 10:12 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Chat with us on WhatsApp