A non conducting ring of radius r has a charge Q. A magnetic field is acting perpendicular to the plane of ting and is changing at a rate if dB/dt. What is torque experienced by the ring.
Asked by anirbanbag81
23rd March 2018,
9:57 AM
Answered by Expert
Answer:
Change in magnetic flux gives Electrical field. This electrical field E and change in magneti flux dΦ/dt are related as follows
if we assume E is uniform over the ring, then 
; we get 
; we get then torque = force × distance = (QE)×r 
Answered by Expert
23rd March 2018,
11:13 AM
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