a motar car starts from rest and accelerate uniformly for 10s to a velocity of 30m/s it then runs at a constant speed and it is finally brought to rest in 80m in constant retardation total distane covered is 830m find the value of acceleration ,retardation,total time taken
Asked by gargpuneet989
7th July 2018,
6:26 PM
Answered by Expert
Answer:
acceleration required to get final speed v=30 m/s in time t=10 s is obtained from " v = u+a×t " , with intial speed u =0;
acceleration a = 30/10 = 3 m/s2
distance S1 travelled while accelerating, S1 = (1/2)a×t2 = (1/2)×3×10×10 = 150 m ..................(1)
retardation ar that is made to stop the car in a distance S3 = 80 m is obtained using " v2 = u2 - 2×ar ×S3 "
with final speed v = 0 and initial speed u = 30 m/s.
ar = (30×30)/(2×80) = 5.625 m/s2
time required to stop the car is obtained from " v = u - ar x t " with final speed v = 0; time = 30/(5.625) = 5.3 s
distance S2 travelled with uniform speed = 830-(80+150) = 600 m ; time of travel with uniform speed = 600/30 = 20 s
total time = 10+20+5.3 = 35.3 s
Answered by Expert
8th July 2018,
9:53 AM
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