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a mobile phone lies along the principal axis of a concave mirror by suitable diagram the formation of its image.explain why the magnification is not uniform. will the distortion of image depend on the location of the phone with respect to the mirror

Asked by jaspreet singh 15th February 2011, 6:57 AM
Answered by Expert
Dear student,

there is a relationship between the object distance and object size and the image distance and image size. Starting from a large value, as the object distance decreases (i.e., the object is moved closer to the mirror), the image distance increases; meanwhile, the image height increases. At the center of curvature, the object distance equals the image distance and the object height equals the image height. As the object distance approaches one focal length, the image distance and image height approaches infinity. Finally, when the object distance is equal to exactly one focal length, there is no image. Then altering the object distance to values less than one focal length produces images that are upright, virtual and located on the opposite side of the mirror. Finally, if the object distance approaches 0, the image distance approaches 0 and the image height ultimately becomes equal to the object height. These patterns are depicted in the diagram below. Nine different object locations are drawn and labeled with a number; the corresponding image locations are drawn in blue and labeled with the identical number.

Hope this helps.
Answered by Expert 18th February 2011, 12:50 PM
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