CBSE Class 11-science Answered
A mixture of pure AgCl and AgBr contains 60.94% Ag by mass. What is the % of AgCl in sample
Asked by Anil | 13 May, 2017, 09:49: PM
Expert Answer
Let x = mass AgCl
Let y = mass AgBr
Moles Ag in 100 g = 60.94g/ 107.868=0.5649
x + y = 100 g
x / 143.3 + y / 187.8 = 0.5649
187.8 x + 143.3 y = 15202
187.8 (100-y) + 143.3 y = 15202
18780 - 187.8 y + 143.3 y = 15202
3578 = 44.5 y
y = 80.40 g = mass AgBr
100 – 80.40 = 19.6 g
% AgCl = 19.6
Answered by Vaibhav Chavan | 15 May, 2017, 11:52: AM
Concept Videos
CBSE 11-science - Chemistry
Asked by drhimasingh | 22 May, 2020, 11:39: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by nareshrajpurohit43109 | 22 May, 2020, 11:18: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by d6knx7qmw1 | 15 May, 2020, 10:37: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by sahadipa1975 | 02 May, 2020, 08:53: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by abhishek19362771 | 08 Apr, 2020, 03:48: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by anilsolanki2060 | 22 Feb, 2020, 10:12: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by pujakurmi22 | 11 Nov, 2019, 10:59: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by jkatwara | 14 Oct, 2019, 12:21: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by vikas.kochhar6 | 30 Aug, 2019, 03:58: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by pb_ckt | 19 May, 2019, 11:56: PM
ANSWERED BY EXPERT