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CBSE Class 11-science Answered

A mixture of pure AgCl and AgBr contains 60.94% Ag by mass what is %  of AgCl in sample
Asked by shahrithik07 | 08 Oct, 2018, 06:44: PM
answered-by-expert Expert Answer
Mass of AgCl + AgBr = 100 g
 
Let the mass of AgCl = x g
 
and the mass of AgBr = (1-x) g
 
 space Moles space of space ag space in space 100 space straight g space equals fraction numerator Weight over denominator Molecular space weight end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 60.94 over denominator 108 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.559 space mol We space have comma Molecular space weight space of space AgCl space equals space 143.5 space straight g divided by mol Molecular space weight space of space AgBrl space equals space 188 space straight g divided by mol Moles space of space AgCl space equals fraction numerator straight x over denominator 143.5 end fraction Moles space of space AgBr space equals space straight y over 188 fraction numerator straight x over denominator 143.5 end fraction space plus space straight y over 188 space equals space 0.56 fraction numerator straight x over denominator 143.5 end fraction space plus space fraction numerator left parenthesis 100 minus straight x right parenthesis over denominator 188 end fraction space equals space 0.56 fraction numerator open parentheses 188 straight x space close parentheses space plus space 143.5 left parenthesis 100 minus straight x right parenthesis over denominator open parentheses 188 cross times space 143.5 close parentheses end fraction space equals space 0.56 fraction numerator open parentheses 188 straight x space close parentheses plus 14350 minus space 143.5 straight x over denominator open parentheses 188 cross times space 143.5 close parentheses end fraction equals space 0.56 44.5 straight x space equals 757.68 straight x space equals 17.02 space
17.02%  of AgCl is present in the sample.
Answered by Varsha | 09 Oct, 2018, 11:48: AM

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