A metal M forms a sulphate which is isomorphous with MgSO4.7H2O. If 0.6538 gm of metals M displaced 2.16gm of silver from silver nitrate solution, then the atomic weight of the metal M is?
Asked by minipkda
18th August 2018,
8:09 PM
Answered by Expert
Answer:
According to law of chemical Equivalence,
gEq (M) = gEq (Ag)
{ 0.6538 × nM}/M = {2.16 × nAg}/MAg
{0.6538 × 2 }/M = {2.16 × 1}/108
So, 2.16M = 141.22
M = 65.38 (May be Cu)
Answered by Expert
23rd August 2018,
2:35 AM
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