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ICSE Class 10 Answered

A man loses a 2.5 M long crowbar to raise a 100 kg mass such that load arm is 0.5 CM the distance moved by the effort is 0.1 M find a.effort needed to lift a load B. Mechanical advantage of crowbar c.the work done by the effort d.distance the load is raised  e.the work done on the Load f. the efficiency of the crowbar
Asked by Samrat | 30 Jun, 2018, 09:10: PM
answered-by-expert Expert Answer
" A man loses  2.5 m long crowbar "  ! ? , I assume " a man uses 1.5 m long crowbar "
 
also " load arm is 0.5 CM " ?,  meaningless statement, i assume "  load arm is 0.5 m "
 
if load arm is 0.5 m , then effort arm is 2 m and mechanical advantage = 2 / 0.5 = 4
 
effort needed to lift a load of 100 kg is 100/4 = 25 kgf
 
workdone = force×distance = 25×9.8×.1 = 24.5 J
 
ideally velocity ratio = Mechanical advantage, hence the load raised = 0.1/4 = 0.025 m = 2.5 cm
 
workdone on the load = 100×9.8x 0.025 = 24.5 J
 
efficiency = 100%
Answered by Thiyagarajan K | 02 Jul, 2018, 05:07: PM

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