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a man drags a block through 10m on rough surface (mew=0.5). A force of root3 kN acting at 30 to the horizontal . the work done by applied force is
Asked by Vedantshinde4may | 25 Feb, 2019, 05:10: PM
answered-by-expert Expert Answer
Work done by force W = FScosΘ 
W=  3000×10×cos30 =  25980.76 Joules
Answered by Ankit K | 26 Feb, 2019, 06:54: PM
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a man drags a block through 10m on rough surface (mew=0.5). A force of root3 kN acting at 30 to the horizontal . the work done by applied force is
Asked by Vedantshinde4may | 25 Feb, 2019, 05:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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