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A man completed a trip of 136 km in 8 hours.Some parts of trip was covered at 15 kmph and the remaining at 18kmph.Find the part of trip covered at 18kmph.

Asked by vismayagirish72 3rd February 2018, 6:31 PM
Answered by Expert
Answer:
begin mathsize 16px style Let space part space covered space at space 15 space kmph space be space straight y space km
Then space part space covered space at space 18 space kmph space will space be space left parenthesis 136 minus straight y right parenthesis space km
Time space equals space fraction numerator Distance space over denominator Speed end fraction
straight y over 15 plus fraction numerator 136 minus straight y over denominator 18 end fraction equals 8
fraction numerator 6 straight y plus 680 minus 5 straight y over denominator 90 end fraction equals 8
straight y plus 680 equals 720
straight x equals 40 space km
Part space covered space at space 15 space kmph space is space 40 space km
Part space covered space at space 18 space kmph space is space 136 minus 40 equals 96 space km end style
Answered by Expert 3rd February 2018, 8:10 PM
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