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CBSE Class 10 Answered

A magnifying lens of focal length of 20 cm is held 10 cm away from the object 0.25 cm l9ng. Find the position, nature of the image, power and magnification of the lens.  
Asked by lakhinandanbora21590 | 11 Jul, 2018, 11:35: PM
answered-by-expert Expert Answer
lens formula :- begin mathsize 12px style 1 over v minus 1 over u space equals space 1 over f end style...............(1)
v = lens to image distance
u = lens to object distance = -10 cm (given value and sign convention is used)
f = focal length = 20 cm (given)
 
by substituting the values of u and f in eqn.(1), we get v = - 20 cm,
it means image also formed in the same side of lens where object is placed.
 
magnification = v/u = (-20)/(-10) = 2 , image is magnified, non-inverted(erect) and virtual.
 
Power of lens = 1/f , f expressed in m .  hence power = 100/20 = +5
 
Answered by Thiyagarajan K | 12 Jul, 2018, 11:19: AM

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