Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

A magnetic needle free to rotate in a vertical parallel to the magnetic meridian has its north tip down at 60° with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0.4 G. Determine the magnitude of the earth's magnetic field at the place.

Asked by Topperlearning User 1st June 2015, 2:09 PM
Answered by Expert
Answer:

Horizontal component of earth's magnetic field, BH =0.4 G

Angle made by the needle with the horizontal plane = Angle of dip = δ= 600

Earth's magnetic field strength = B

We can relate B and BH as:

Hence, the strength of earth's magnetic field at the given location is 0.8G.

Answered by Expert 1st June 2015, 4:09 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp