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ICSE Class 10 Answered

A machine is given by a 200 kg mass falling at 8 m in 5 second lifts a load of 100 kg calculate the power input the machine if the efficiency of machine is 80% calculate the height of to which the load is raised in 5 seconds
Asked by Samrat | 30 Jun, 2018, 11:10: PM
answered-by-expert Expert Answer
velocity of falling mass 200 kg from a height 8 m is obtained using the formula " v2 = 2gh " , assuming falling from rest.
 
hence velocity v = begin mathsize 12px style square root of 2 cross times 9.8 cross times 8 space end root space equals space 12.52 space m divided by s end style
input power = force×velocity = 200×9.8×12.52 = 24.539 kW
 
80% of input power = output power = (m×g×h)/t
 
hence, 0.8×24.539×103 = (100×9.8×h)/5  ;  we get h = 100.16 m
Answered by Thiyagarajan K | 01 Jul, 2018, 04:45: PM

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